3x^2+5-164=0

Solution for 3x^2+5-164=0 equation:

3x^2+5-164=0

We add all the numbers together, and all the variables

3x^2-159=0

a = 3; b = 0; c = -159;
Δ = b2-4ac
Δ = 02-4·3·(-159)
Δ = 1908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1908}=\sqrt{36*53}=\sqrt{36}*\sqrt{53}=6\sqrt{53}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{53}}{2*3}=\frac{0-6\sqrt{53}}{6}
=-\frac{6\sqrt{53}}{6}
=-\sqrt{53}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{53}}{2*3}=\frac{0+6\sqrt{53}}{6}
=\frac{6\sqrt{53}}{6}
=\sqrt{53}
$